A linear
spring has a potential energy of 25 J and a constant of 510 N/m. How
far has it been stretched?
spring potential energy: Us = 25 J
spring constant: k = 510 N/m
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Starting formula |
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Algebra: multiply each side by 2 |
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Algebra: 2's cancel on right |
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Algebra: divide each side by k |
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Algebra: k's cancel on right |
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Algebra: take square root of each side |
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Algebra: square root of x^2 is x |
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Algebra: switch left and right |
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Plug in numbers with units |
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Math: sqrt(2(25)/510) = 0.313.... |
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Final result with significant figures and unit |
